9.4 : Получение алкинов: реакция алкилирования

One of the two main approaches to preparing alkynes involves alkylation of terminal alkynes to form longer carbon-chain alkynes.

The preparation of alkynes using the alkylation approach proceeds in two steps.

The first step is a deprotonation reaction where a terminal alkyne reacts with a strong base like sodium amide to form the acetylide ion.

The second step is a substitution reaction in which the acetylide ion reacts with a primary alkyl halide to yield a longer carbon–chain alkyne.

Since a new alkyl group gets added to the starting alkyne, the reaction is called an alkylation reaction.

Recall that an acetylide ion is a strong base and can function as a strong nucleophile.

The substitution reaction follows an S_N2 mechanism in which the nucleophilic acetylide ion attacks the positively polarized carbon of the alkyl halide from a direction opposite to the halide leaving group.

This results in a transition state with a partially formed carbon–carbon bond and a partially broken carbon–halogen bond. The displacement of the leaving group yields the product with an inverted stereochemistry at the reaction center.

The S_N2 reaction is most efficient with unhindered alkyl halides like methyl halide and other primary alkyl halides, which are less sterically hindered allowing for the simultaneous nucleophilic attack and departure of the leaving group.

In contrast, with the bulky secondary and tertiary alkyl halides, acetylide ions act as strong bases and undergo an E2 elimination instead of substitution.

Alkylation of terminal alkynes is a useful method to synthesize longer carbon-chain alkynes. For example, deprotonation of acetylene and subsequent reaction with methyl bromide yields 1-propyne. This terminal alkyne can be further deprotonated and made to react with a different alkyl halide, like ethyl bromide, to form an internal alkyne, 2-pentyne.